Bài làm:
Ta có: \(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x\)
\(\Leftrightarrow2x=\frac{2401}{144}+\frac{961}{144}\)
\(\Leftrightarrow2x=\frac{1681}{72}\)
\(\Rightarrow x=\frac{1681}{144}\)
=> \(y^2=\frac{1681}{144}+\frac{961}{144}=\frac{2642}{144}\)
=> \(y=\pm\frac{\sqrt{2642}}{12}\)
Tìm x, y biết
x + [ -31/122 ) =( 49 /12) 2 -x= y2
Tìm x,y biết: x + (-31/12)^2 = (49/12)^2 - x = y^2
Tìm x;y biết rằng:
\(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
Tìm x,y biết
\(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
Tìm x,y
a, x+(–31/12)^2=(49/12)^2–x=y^2
b, x*(x-y)=3/10 và y*(x-y)=–3/20
Tìm x, y:
\(x+\left(\frac{-31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
\(x+\frac{-31}{12}^2=\frac{49}{12}^2-x=y^2\)
Tìm x,y
tìm x,y biết : a) x+(-31/12)^2= (-49/12)^2-x = y^2
b) 5^x . (5^3)^2 = 625
c) (12/25)^2=(5/3)^-2 - (-3/5)^4
Bài 2 Tìm x,y : \(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
