Question

tìm x,y biết 

\(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+3y-1}{6x}\)

Answer 1

\(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+1+3y-2}{5+7}=\frac{2x+3y-1}{12}=\frac{2x+3y-1}{6x}\)

=>12=6x

=>x=2

=>3y-2/7=1

=>3y-2=7

=>3y=9

=>y=3

vậy x=2 ; y=3

Answer 2

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