Question

tìm x,y biết \(\dfrac{1+2y}{18}=\dfrac{1+4y}{24}=\dfrac{1+6y}{6x}\)

Answer 1

\(\dfrac{1+2y}{18}=\dfrac{1+6y}{6x}\\ \Rightarrow\dfrac{1+2y}{18}=\dfrac{1+6y}{6x}=\dfrac{\left(1+2y\right)+\left(1+6y\right)}{18+6x}\\ =\dfrac{2+8y}{18+6x}=\dfrac{1+4y}{9+3x}\\ \Rightarrow9+3x=24\\ \Rightarrow3x=15\\ \Rightarrow x=5\)

Answer 2

Ta có: \(\dfrac{1+2y}{18}+\dfrac{1+4y}{24}\)

\(\Rightarrow24+48y=18+72y\)

\(\Rightarrow6=24y\Rightarrow y=\dfrac{1}{4}\)

\(\Rightarrow\dfrac{1+\dfrac{1}{2}}{18}+\dfrac{1+\dfrac{3}{2}}{6x}\)

\(\Rightarrow9x=45\Rightarrow x=5\)

Answer 3