\(\dfrac{1+2y}{18}=\dfrac{1+4y}{24}=\dfrac{1+6y}{6x}\)
\(\dfrac{1+2y}{18}=\dfrac{1+6y}{6x}=\dfrac{2+8y}{18+6x}=\dfrac{1+4y}{9+3x}\\ \Rightarrow9+3x=24\\ \Rightarrow3x=15\\ \Rightarrow x=5\)
Ta có : \(\dfrac{1+2y}{18}=\dfrac{1+4y}{24}=\dfrac{1+6y}{6x}\)
Theo tính chất của dãy tỉ số bằng nhau :
\(\dfrac{1+2y+1+4y+1+6y}{18+24+6x}=\dfrac{3+12y}{42+6x}=\dfrac{3\left(1+4y\right)}{3\left(14+2y\right)}=\dfrac{1+4y}{14+2y}\)
Ta thấy :\(\dfrac{1+4y}{24}=\dfrac{1+4y}{14+2y}\)
\(\Leftrightarrow14+2y=24\Rightarrow2y=10\Leftrightarrow y=5\)
Xét \(\dfrac{1+4y}{24}=\dfrac{1+6y}{6x}\)
\(\Rightarrow\dfrac{21}{24}=\dfrac{31}{6x}\)
\(\Rightarrow31.24=21.6x\Leftrightarrow744=126.x\)
\(\Rightarrow x=744:126=\dfrac{744}{126}\)
