Ta có :
\(\dfrac{1+2y}{18}=\dfrac{1+4y}{24}\)
\(\Leftrightarrow24\left(1+2y\right)=18\left(1+4y\right)\)
\(\Leftrightarrow24+48y=18.72y\)
\(\Leftrightarrow24-18=72y-48y\)
\(\Leftrightarrow6=24y\)
\(\Leftrightarrow y=\dfrac{1}{4}\)
Thay \(y=\dfrac{1}{4}\) ta có :
\(\dfrac{1+1}{24}=\dfrac{1+\dfrac{3}{2}}{6x}\)
\(=\dfrac{1}{12}=\dfrac{\dfrac{5}{2}}{6x}\)
\(\Leftrightarrow6x=\dfrac{5}{2}.12\)
\(\Leftrightarrow6x=30\)
\(\Leftrightarrow x=5\)
*ta có:
\(\dfrac{1+2y}{18}\)=\(\dfrac{1+4y}{24}\)
<=>(1+2y).24=18.(1+4y)
<=>24+48y =18+72y
<=>24-18 = 72y-48y
<=>6 = 24y
<=> y =\(\dfrac{1}{4}\)
* Thay y=\(\dfrac{1}{4}\)vào tỉ lệ thức\(\dfrac{1+4y}{24}\)=\(\dfrac{1+6y}{6x}\),ta có:
\(\dfrac{1+4^{\dfrac{1}{4}}}{18}\)\(\)=\(\dfrac{1+6\dfrac{1}{4}}{6x}\)
<=>\(\dfrac{1+1}{24}\)=\(\dfrac{1+\dfrac{3}{2}}{6x}\)
<=>\(\dfrac{1}{12}\)=\(\dfrac{\dfrac{5}{2}}{6x}\)
<=>\(\dfrac{1}{12}\)=\(\dfrac{5}{12x}\)
<=>12.5=12x
<=>x=5
Vậy x=5;y=\(\dfrac{1}{4}\)
