Các câu hỏi tương tự
Tìm x
\(2x.\left(x-5\right)-x.\left(3+2x\right)=26\)
\(\left(x-7\right).\left(x-5\right)-12.\left(3x-7\right)=15\)
\(4.\left(18-5x\right)-12.\left(3x-7\right)=15.\left(2x-16\right)-6.\left(x+14\right)\)
\(\left(x-1\right).\left(x^2+x+1\right)=x^3-2x\)
Chứng Minh rằng giá trị của các biểu thức sau ko phụ thuộc vào biến:
a)\(\left(2-x\right)\left(1+2x\right)+\left(1+x\right)-\left(x^4+x^3-5x^2-5\right)\\ \)
\(b)\left(x^2-7\right)\left(x+2\right)-\left(2x-1\right)\left(x-14\right)+x\left(x^2-2x-22\right)+35\)
BÀI 6 tìm x1,2xleft(x-5right)-left(3x+2x^2right)0 2,xleft(5-2xright)+2xleft(x-1right)133,2x^3left(2x-3right)-x^2left(4x^2-6x+2right)0 4,5xleft(x-1right)-left(x+2right)left(5x-7right)65,6x^2-left(2x-3right)left(3x+2right)1 6,2xleft(1-xright)+59-2x^2
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BÀI 6 tìm x
1,\(2x\left(x-5\right)-\left(3x+2x^2\right)=0\) 2,\(x\left(5-2x\right)+2x\left(x-1\right)=13\)
3,\(2x^3\left(2x-3\right)-x^2\left(4x^2-6x+2\right)=0\) 4,\(5x\left(x-1\right)-\left(x+2\right)\left(5x-7\right)=6\)
5,\(6x^2-\left(2x-3\right)\left(3x+2\right)=1\) 6,\(2x\left(1-x\right)+5=9-2x^2\)
24 tháng 7 2023 lúc 9:35
Tìm x:
a, \(x-2=\left(x-2\right)^2\)
b,\(x+5=2\left(x+5\right)^2\)
c,\(\left(x^2+1\right)\left(2x-1\right)+2x=1\)
d,\(\left(x^2+3\right)\left(x+1\right)+x=1\)
Tìm x a, dfrac{left(x+2right)^2}{2} + dfrac{left(1+2xright)^2}{4} + dfrac{left(1-2xright)^2}{8} – (1 + x)2 0b, dfrac{left(x+1right)^2}{2} - dfrac{left(1-2xright)^2}{3} + dfrac{left(1+2xright)^2}{4} - dfrac{left(5-xright)^2}{6} 0c, (3 + x)3 – 3x2(x + 4) + (x + 2)3 (1 – x)3 – 8
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Tìm x
a, \(\dfrac{\left(x+2\right)^2}{2}\) + \(\dfrac{\left(1+2x\right)^2}{4}\) + \(\dfrac{\left(1-2x\right)^2}{8}\) – (1 + x)2 = 0
b, \(\dfrac{\left(x+1\right)^2}{2}\) - \(\dfrac{\left(1-2x\right)^2}{3}\) + \(\dfrac{\left(1+2x\right)^2}{4}\) - \(\dfrac{\left(5-x\right)^2}{6}\)= 0
c, (3 + x)3 – 3x2(x + 4) + (x + 2)3 = (1 – x)3 – 8
P=\(\left(\dfrac{3\left(x+2\right)}{2x^2+8}-\dfrac{2x^2-x-10}{\left(x+1\right)\left[\left(x+1\right)^2-2x\right]}\right):\left(\dfrac{5}{x^2+1}+\dfrac{3}{2\left(x+1\right)}-\dfrac{3}{x-1}\right)\cdot\dfrac{2}{x-1}\)
a) rút gọn P
b)tìm tất cả các giá trị nguyên của x để P có giá trị là bội của 4
Bài 1. (2 điểm) Thu gọn các biểu thức:
a) $\left(-12{{x}^{13}}{{y}^{15}}+6{{x}^{10}}{{y}^{14}} \right) \, : \, \left(-3{{x}^{10}}{{y}^{14}} \right);$
b) $\left(x-y \right)\left({{x}^{2}}-2x+y \right)-{{x}^{3}}+{{x}^{2}}y.$
Giải phương trình:
a) \(x^2-3\left|x\right|-4=0\)
b) \(\left(x-2\right)^2+\left|x-5\right|-x^2-14=0\)
c) \(\left(x+1\right)^2-\left|3-2x\right|-\left(x+2\right)^2+6=0\)
d) \(x^2+4x+3+\left|2x-5\right|-\left(x+1\right)\left(x+3\right)-5+2x=0\)
Tìm x: \(\left(x+3\right)^3-x\left(3x+1\right)^2+\left(2x+1\right)\left(4x^2-2x+1\right)-3x^2=54\)
tìm GTLN
a)\(A=x^2+5y^2+2xy-4x-8y+2015\)
b)\(B=\left(x-2012\right)^2+\left(x+2013\right)^2\)
c)\(C=\left(x-1\right)\left(2x-1\right)\left(2x^2-3x-1\right)+2017\)
d)\(D=\left(x-1\right)\left(x-3\right)\left(x-4\right)\left(x-6\right)+10\)