Question

Tìm x:

(x+1)+(x+2)+(x+3)+......+(x+100)=7450

Mình đang cần gấp 

Answer 1

(x + 1 ) + (x + 2) + (x + 3) + ... + (x + 100) = 7450

(x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 7450

     100 số x                    100 số hạng

100.x + (1 + 100).100:2 = 7450

100.x + 101.50 = 7450

100.x + 5050 = 7450

100.x = 7450 - 5050

100.x = 2400

x = 2400 : 100

x = 24

Vậy x = 24

Answer 2

(x+1)+(x+2)+(x+3)+......+(x+100)=7450

=> 100x + (1 + 2 + 3 + ...+ 100) = 7450 

=> 100x + 5050 = 7450

=> 100x = 2400

=> x = 24

Answer 3

(x+1)+(x+2)+(x+3)+...+(x+100)=7450

(x+x+x+...+x)+(1+2+3+...+100)=7450

100x+5050=7450

100x=7450-5050

100x=2400

x=24.

Answer 4

(x + 1 ) + (x + 2) + (x + 3) + ... + (x + 100) = 7450

(x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 7450

     100 số x                    100 số hạng

100.x + (1 + 100).100:2 = 7450

100.x + 101.50 = 7450

100.x + 5050 = 7450

100.x = 7450 - 5050

100.x = 2400

x = 2400 : 100

x = 24

Vậy x = 24

Answer 5

thg Edogawa Conan copy bài t

Answer 6

( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 7450

( x + x + x + ... + x ) + ( 1 + 2 + 3 + ... + 100 )= 7450

100x + 5050 = 7450

100x = 7450 - 5050

100x = 2400

x = 2400 :100

x = 24

Answer 7

( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 7450

( x + x + x + ... + x ) + ( 1 + 2 + 3 + ... + 100 )= 7450

100x + 5050 = 7450

100x = 7450 - 5050

100x = 2400

x = 2400 :100

x = 24

Answer 8

( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 7450

( x + x + x + ... + x ) + ( 1 + 2 + 3 + ... + 100 )= 7450

100x + 5050 = 7450

100x = 7450 - 5050

100x = 2400

x = 2400 :100

x = 24

Answer 9

Óc chó vcl

Answer 10

\(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=7450\)

\(=\left(x+x+...+x\right)+\left(\frac{\left(100+1\right).100}{2}\right)=7450\)

\(=100x+\frac{101.100}{2}=7450\)

\(=>100x+101.50=7450\)

\(=>100x+5050=7450\)

\(=>100x=7450-5050=2400\)

\(=>x=24\)

Answer 11

\(\left(x+1\right)\left(x+2\right)\left(x+3\right) +......+\left(x+100\right)=7450\)

\(\Leftrightarrow\left(x+x+x+...+x\right)+\left(1+2+3+.....+100\right)=7450\)

            100 số x                                              100 số hạng

\(\Leftrightarrow100x+\left(1+100\right).100:2=7450\)

\(\Leftrightarrow100.x+101.50=7450\)

\(\Leftrightarrow100x+5050=7450\)

\(\Leftrightarrow100x=7450-5050=2400\)

\(\Leftrightarrow x=2400:100=24\)