Question

Tim x

(X+1)².(X-1)²=0

 

Answer 1

\(\left(x+1\right)^2\left(x-1\right)^2=0\)

\(\Rightarrow\orbr{\begin{cases}\left(x+1\right)^2=0\\\left(x-1\right)^2=0\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x+1=0\\x-1=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0-1=-1\\x=0+1=1\end{cases}}\)

Vậy: \(x\in\left\{1;-1\right\}\)

Answer 2

x=1

x=-1

Answer 3

(x+1)².(x-1)²=0

=> x+1=0  hoac x-1=0

=> x=0-1  hoac  x=0+1

=> x=-1  hoac x=1

Answer 4

=>\(\orbr{\begin{cases}\left(x-1\right)^2=0\\\left(x+1\right)^2=0\end{cases}}\)

+ (x-1)²=0

=>(x-1)²=0²

=>x-1=0

=>x=0+1

x=1

+(x+1)²=0

=>x+1=0           (k thỏa mãn)

=>x=1

vay x=1

k mình nha