(x+1/2).(2/3-2x)=0
suy ra x+1/2=0
x =0-1/2=-1/2
2/3-2x=0
2x=0+2/3=2/3
x=2/3:2=1/3
==> x+1/2=0 hoặc 2/3 - 2x =0
==> x=-1/2 hoac x=1/3
vì tích = 0 nên 1 trong 2 số = 0
giả sử x + 1/2 = 0
=>x = 0 - 1/2 = -1/2
giả sử 2/3 - 2x = 0
=>2x = 2/3 - 0 = 2/3
=> x=1/3
\(\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\)
\(\Rightarrow x+\frac{1}{2}=0hay\frac{2}{3}-2x=0\)
\(x=\frac{-1}{2}hay2x=\frac{2}{3}\)
\(x=\frac{-1}{2}hayx=\frac{1}{3}\)