\(\left(x+1\right)^2-\left(x+2\right)^2=0\)
\(\Rightarrow\left[\left(x+1\right)+\left(x+2\right)\right]\left[\left(x+1\right)-\left(x+2\right)\right]=0\)
\(\Rightarrow\left[2x+3\right]\left(-1\right)=0\)
\(\Rightarrow2x+3=0\)
\(\Rightarrow2x=-3\)
\(\Rightarrow x=-\frac{3}{2}\)
Vậy ...