(x+1)2-(x+1)=0
<=> (x+1)2 hoặc x+1=0
(x+1)2=0 => x=-1
x+1=0 => x=-1
Vậy x=-1
b) 5x2-13x=0
x(5x-13)=0
<=> x=0 hoặc 5x-13=0
5x-13=0 => 5x=13 => x=13/5
Vậy x=13/5
c) x2-7x3=0
<=> x(x-7x2)=0
=> x=0 hoặc
(x+1)2-(x+1)=0
<=> (x+1)2 hoặc x+1=0
(x+1)2=0 => x=-1
x+1=0 => x=-1
Vậy x=-1
b) 5x2-13x=0
x(5x-13)=0
<=> x=0 hoặc 5x-13=0
5x-13=0 => 5x=13 => x=13/5
Vậy x=13/5
c) x2-7x3=0
<=> x(x-7x2)=0
=> x=0 hoặc
Tìm x biết x2_7x3 giai giup mình dung ghi dap an mình ko hieu
Tìm x biết 4x3-x2 = 0 Chi mình bai nha dung ghi dap an mình ko hieu
Tìm a,b để P(x) chia het cho Q(x):
1) P(x) = x^3 + ax^2 + 3x +b; Q(x)=x(x-1)
2) P(x) = 2x^4 -5x^3+3ax^2 +bx +1 ; Q(x)=x^2- 3x+2
Cac ban giai giup minh nha,thanks
Tim so nguyen x de (2x+5) chia het cho (3x2+2x+2). Cac ban giai giup minh nhe...cam on nhieu
Giai phuong trinh giup minh
Cho bieu thuc B=(1/x-3-1/x^2-9)*(1/x+2+1)
Tim ĐKXĐ cua B
Rut gon B
TIm x nguyen de bieu thuc B co gia tri nguyen
a) (x-1/2).(1+5x)=0
b) |2x-1|=|x+2|
c) 2.3^x.3^2=18(xeN)
d) x+2/5=2-3x/3
e) 7x=3y va x-y=32
giAI GIUP MINH MAY BAI NAY
co ai giai dc bai nay ko a
1) ( a+b ) ( a+ b)
2) ( a+b ) (a - b )
3) ( a - b ) ( a+ b )
bai tap nay thay minh dua ra
giai het giup minh vs a
c.on trc
tim x de A thuoc Z biet A=x^2-3x+1/x+1 .Moi nguoi giup minh giai bai nay trong trua nay nha
7(2x-5)-5(7x-2)+2(5x-7) = (x+2)-(x+4) tim x nhe ai giai giup minh vs