x10 : x7 = 1/27
=> x10-7 = 1/27
=> x3 = 1/27 = (1/3)3
=> x = 1/3
Vậy x = 1/3
\(x^{10}\div x^7=\frac{1}{27}\)
\(x^3=\left(\frac{1}{3}\right)^3\)
\(x=\frac{1}{3}\)
In the figure below, x = Câu 2 Find the measure of angle J if \widehat{K}=29^o K =29 o and angle J and K are supplementary. Answer: \widehat{J}= J = ^o o . Câu 3 In the figure below, x = Câu 4 In the figure below, x = Câu 5 Solve: |2x-3|-4=3∣2x−3∣−4=3, where xx is a negative number. Answer: x=x= Câu 6 Calculate: 9+|-6|:1^2 =9+∣−6∣:1 2 = Câu 7 Compare: \dfrac{36}{27} 27 36 \dfrac{4}{3} 3 4 Câu 8 Find the negative number yy such that |y+\dfrac{7}{2}|-\dfrac{1}{2}=4∣y+ 2 7 ∣− 2 1 =4. Answer: y=y= Câu 9 Find xx such that \dfrac{32}{2^x}=2 2 x 32 =2. Answer: x=x= Câu 10 Find nn such that \dfrac{(-4)^n}{64}=-16 64 (−4) n =−16. Answer: n=n= Cần gấp nhé
Tìm x
x+(13-15)=5+(10-7)
Bài 1: Tính: A= \(\frac{81^{10}.3^{17}}{27^{10}.9^{13}}\)
Bài 2: Tìm x, y: \(\frac{x}{7}=-\frac{12}{49}\)
Tìm x biết
\(\left(\frac{1}{3}\right)^x+\left(\frac{1}{3}\right)^{x+2}=\frac{10}{27}\)
Tìm a và b biết 2.a = 7.b và 2a + 7b = 28
1, tìm x, biết :
a, 3(x+1)+4x=10
b, |x+3|=|5-3x|
c, x+1/10+x+2/9=x+3/8+x+4/7
d, x+1/11+x-12/12+x-27/13=x+12/47-5
nhờ mn giúp mk với ạ!
1/ Rút gọn
\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8-6^8.20}\)
\(B=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
2/ Tìm x
\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
(3x + 1/4) mũ 3 = -27
x mũ 7/ 81 = 27
x mũ 10 = 25x mũ 8
(x mũ 2) mũ 4 = x mũ 18/ x mũ 10
x10:x7=1/27
Tìm x
a)x+2x+3x+4x+...+100x=-213
b)x+1/3=x-2/4
c)x-6/7+x-7/8+x-8/9=x-9/10+x-10/11
d)x+32/11+x+23/12=x+38/13+x+27/14
e)x-1/2004+x-2/2003-x-3/2002+x-4/2001
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