Ta có : \(\frac{x+1}{2017}+\frac{x+1}{2016}=\frac{x+1}{2015}+\frac{x+1}{2014}\)
\(\Rightarrow\frac{x+1}{2017}+\frac{x+1}{2016}-\frac{x+1}{2015}-\frac{x+1}{2014}=0\)
\(\Rightarrow\left(x+1\right)\left(\frac{1}{2017}+\frac{1}{2016}-\frac{1}{2015}-\frac{1}{2014}\right)=0\)
Vì \(\left(\frac{1}{2017}+\frac{1}{2016}-\frac{1}{2015}-\frac{1}{2014}\right)\ne0\)
Nên : x + 1 = 0
=> x = -1
Vậy x = -1 .
x^2013+y^2013=x^2014+y^2014=x^2015+y2015 tinh x^2016+y^2016
tìm x biết
\(\frac{x-1}{2016}+\frac{x-2}{2015}+\frac{x-3}{2014}+...+\frac{x-2016}{1}=2016\\ \)
Tính A = x2016 - 2016.x2015 + 2016.x2014 - 2016.x2013 + ... + 2016x2 - 2016x +2016 tại x = 2015
tìm x biết: x-1/ 2016 + x-2/ 2015+ x-3/ 2014 +....+ x-2016/1 = 2016
Mình phải nộp gấp nên đúng mình tick cho nha
tinh nhanh bieu thuc sau
a) x^6-20x^5-20x^4-20x^4-20x^3-20x^2-20x+1992 voi x= 21
b)x^7-26x^6+27x^5-47x^4-77x^3+50x^2+x+1989 tai x = 25
c)4029-2015x+2015x^2-....+2015x^2014-x^2015 tai x= 2014
d)A= (x-1/x-2015+x-2/x-2014+x-3/x-2013+....+x-2014/x-2+x-2015/x-1):(1/2 +1/3+1/4+....+1/2016) tai x=2016 dau / o day la phan do nha!!
xin nho cac ban giai giup cho minh! cam on nhieu!!!!!!!! minh dang can ket qua gap
\(\dfrac{x}{2012}\) +\(\dfrac{x+1}{2013}\)+\(\dfrac{x+2}{2014}\)+\(\dfrac{x+3}{2015}\)+\(\dfrac{x+4}{2016}\)=5
Tìm x:
2-x/2014 - 1 = 1 - x/2015 - x/2016
Giúp mk vs nhé!!!
\(\dfrac{x+1}{2012}+\dfrac{x+2}{2011}+\dfrac{x+3}{2010}=\dfrac{x-1}{2014}+\dfrac{x-2}{2015}+\dfrac{x-3}{2016}\)
giúp tôi giải bài toán:(x+1)/2016)+(x+2)/2015)+(x+3)/2014)+(x+4)/2013)=0
