Question

Tìm x:

\(x-5=0\)

\(x\times7=14\)

\(x+2=6\)

Answer 1

x-5=0

x=0+5

x=5

x*7=14

x=14:7

x=2

x+2=6

x=6-2

x=4                            

Answer 2

a) x - 5 = 0

=> x     = 0 + 5

=> x      = 5

b) x . 7 = 14 

=> x     = 14 : 7

=> x      = 2

c) x + 2 = 6

=> x      = 6-2

=> x       = 4

Ai k mik mik k lại

Answer 3

a. \(x-5=0\)

\(x=0+5\)

\(x=5\)

b. \(x.7=14\)

\(x=14:7\)

\(x=2\)

c.  \(x+2=6\)

\(x=6-2\)

\(x=4\)

Answer 4

\(x-5=0\)

\(x=0+5=5\)

\(x\cdot7=14\)

\(x=\frac{14}{7}=2\)

\(x+2=6\)

\(x=6-2=4\)

Answer 5

x - 5 = 0 

x     = 0 + 5 

x     = 5 

x * 7 = 14 

x      = 14 : 7 

x      = 2

x + 2 = 6 

x       = 6 - 2 

x       =  4

Answer 6

Ta có:

x - 5 = 0

x = 0 + 5

x = 5

X x 7 = 14

X = 14 : 7

X = 2

x + 2 = 6

x = 6 - 2

x = 4

Answer 7

x-5=0

x=5

x*7=14

x=2

x+2=6

x=4

Answer 8

a) x-5=0 

   x=0+5

    x=5

b) X x 8=14

          x=14:7

             x=2

c) x+2=6

        x=6-2

         x=4

Answer 9

Ta có:

x - 5 = 0

x = 0 + 5

x = 5

X x 7 = 14

X = 14 : 7

X = 2

x + 2 = 6

x = 6 - 2

x = 4

Answer 10

X - 5 = 0 <=> X = 0 + 5 =>X =5

X x 7 = 14 <=> X = 14 : 7 => X =2

X + 2 = 6 <=> X = 6 - 2 = 4