\(\left(x+2\right).\left(3x-2\right)-\left(3x-1\right).\left(x-5\right)=11\)
\(\Rightarrow3x^2-2x+6x-4-\left(3x^2-15x-x+5\right)=11\)
\(\Rightarrow3x^2-2x+6x-4-3x^2+15x+x-5=11\)
\(\Rightarrow20x-9=11\)
\(\Rightarrow20x=20\Rightarrow x=1\)
(x + 2)(3x - 2) - (3x - 1)(x - 5) = 11
=> 3x2 - 2x + 6x - 4 - 3x2 + 15x + x - 5 = 11
=> 20x - 9 = 11
=> 20x = 11 + 9
=> 20x = 20
=> x = 20 : 20
=> x = 1
(x + 2).(3x - 2) - (3x - 1).(x - 5) = 11
--> 3x2 - 2x + 6x -4 - 3x2 - 15x - x + 5 = 11
--> -12x = 10
--> x = \(\frac{-5}{6}\)
Vậy x = \(\frac{-5}{6}\)
~ Học tốt ~
\(\left(x+2\right).\left(3x-2\right)-\left(3x-1\right).\left(x-5\right)=11\)
\(\Rightarrow3x^2-2x+6x-4-\left(3x^2-15x-x+5\right)=11\)
\(\Rightarrow3x^2-2x+6x-4-3x^2+15x+x-5=11\)
\(\Rightarrow20x-9=11\)
\(\Rightarrow20x=11+9\)
\(\Rightarrow20x=20\)
\(\Rightarrow\)\(x=20:20\)
\(\Rightarrow x=1\)