\(x\left(x-7\right)-2\left(7-x\right)=0\)
\(=>x\left(x-7\right)+2\left(x-7\right)=0\)
\(=>\left(x+2\right)\left(x-7\right)=0\)
\(=>\left\{{}\begin{matrix}x+2=0=>x=\left(-2\right)\\x-7=0=>x=7\end{matrix}\right.\)
Bài 4: Tìm x:
1) x2 - 9x = 0 2) x(x - 4) – x2 = 7 3) 3x + 2(x – 5) = 5
4) 25x2 - 1 = 0 5) 3x(x - 2) - 5(x - 2) = 0 6) 3x(x - 7) + 4(x – 7) = 0
7) 4x2 – 9 = 0 8) 10x(x - 4) + 2x - 8 = 0 9) x(2x - 5) - 2x2 = 0
10) 2x2 – 4x = 0 11) 2x(3 - 4x) + 3(4x - 3) = 0 12) 2x (x – 5) – 2x2 = 3
mọi người giúp mình vs chiều 1g mình thi rồi! cảm ơn!
Tìm x biết:
a) (x - 4)^2 = (x - 4)
b) 5x^2(x - 7) - 7(7 - x) = 0
c) x^3 - 3x^2 - x + 3 = 0
d) x^3 - 4x + x - 4 = 0
Tìm x biết: (x-3)^2-16=0
x^2 -2x=24
(2x+1)+(x+3)^2(x+7)(x-7)=0
tìm x
(x+4)2- (x+1)(x-1)= 16
(2x-1)2+ (x+3)2- 5(x+7)(x-7)=0
tìm x, biết:
a)x^2+3x=0
b)x.(x-7).(x+7)=0
c)x^3-9x=0
d)x^2-5x-6=0
Tìm x biết:
a) (x+2)^2 - 9 = 0
b) 25x^2 - 10x + 1 = 0
c) x^2 + 14x + 49 = 0
d) (2x-1)^2 + (x+3)^2 - 5(x+7) (x-7) = 0
Tìm x :
\(\text{|x-3|+|2x+1|=4 }\)
\(\text{|2x+3|+|3-4x|=x }\)
\(\text{|x+1|+|x+3|+|2x+7|=x}\)
TÌM X:
1,3x(x-2020)-x+2020=0
2,4-9x^2=0
3,x^2-x+1/4=0
4,x(x-3)+(x-3)=0
5,9x(x-7)-x+7=0
tìm x a)(x+4)^2-(x+1)(x-1)=0 b)(2x-1)^2+(x+3)^2-5(x+7)=0 c)3(x-7)+(5-x)=2^3(x-1)
bài 9:tìm x
1) (x-3)^2-4=0
2) x^2-2x=24
3) (2x-1)^2+(x+3)^3-5(x+7)(x-7)=0
giúp mình với mn ơi
