|x+15|=27-x2
=>x+15=27-x2 hoặc -(27-x2)
Với x+15=27-x2=>x2+x-12=0
=>x2-3x+4x-12=0
=>x(x-3)+4(x-3)=0
=>(x+4)(x-3)=0
=>x=-4 hoặc x=3
Với x+15=-(27-x2) cái này vô nghiệm nhưng ko bik lm sao vs lại dạng này tui hơi gà
Tìm x
\(\left(x^4\right)^2=\frac{x^{12}}{x^5}\left(x\ne0\right)\)
\(\left(3x-1\right)^3=\frac{8}{27}\)
\(x^2-19=5.9;\left(2x+1\right)^3=-0,001;\left(\dfrac{5}{6}\right)^{2x-1}=\left(\dfrac{5}{6}\right)^5;\left(\dfrac{1}{3}x-\dfrac{2}{3}\right)^3=27;\left(\dfrac{1}{32}\right)^x=\left(\dfrac{1}{2}\right)^{15}\)
tìm X biết
\(5^x.\left(5^3\right)^2=625\)
\(27< 81^3:3^x< 243\)
\(\left(5x+1\right)^2=\frac{36}{49}\)
\(\left(x-\frac{2}{9}\right)^3=\left(\frac{2}{3}\right)^6\)
giúp mình vs nha
Tìm x, biết:
\(\left(x-\frac{2}{3}\right)^3=\frac{-1}{27}\)
Ai nhanh nhất mik tick 3 cái nè
Tìm x
\(\frac{2}{\left(x+2\right).\left(x+4\right)}+\frac{4}{\left(x+4\right).\left(x+8\right)}+\frac{6}{\left(x+8\right).\left(x+14\right)}=\frac{x}{\left(x+2\right).\left(x+14\right)}\)
Tìm x
\(\frac{2}{\left(x+2\right).\left(x+4\right)}+\frac{4}{\left(x+4\right)\left(x+8\right)}+\frac{6}{\left(x+8\right)\left(x+14\right)}=\frac{x}{\left(x+2\right).\left(x+14\right)}\)
Tìm x
\(\frac{1}{x.\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}-\frac{1}{x}=\frac{1}{2017}\)
a) tìm x biết:\(2014.\left|x-12\right|+\left(x-12\right)^2=2013.\left|12-x\right|\)
b) tìm giá trị lớn nhất của biểu thức :\(A=\frac{3}{\left(x+2\right)^2+4}\)
Tìm x
\(\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}-\frac{1}{x}=\frac{1}{2017}\)
