Question

Tìm x

\(\left|x-\frac{1}{3}\right|=\frac{5}{6}\)

Các bạn giúp mình với!!!

Answer 1

\(|x-\frac{1}{3}|=\frac{5}{6}\)

\(\Rightarrow x-\frac{1}{3}=\frac{5}{6}\) hoặc \(x-\frac{1}{3}=-\frac{5}{6}\)

\(\Rightarrow x=\frac{5}{6}+\frac{1}{3}\) hoặc \(x=-\frac{5}{6}+\frac{1}{3}\)

\(\Rightarrow x=\frac{7}{6}\) hoặc \(x=-\frac{3}{6}=-\frac{1}{2}\)

Answer 2

\(\left|x-\frac{1}{3}\right|=\frac{5}{6}\)

=> Các trường hợp

TH1 : \(x-\frac{1}{3}=\frac{5}{6}\)

\(x=\frac{5}{6}+\frac{1}{3}\)

\(x=\frac{7}{6}\)

TH2 : \(x-\frac{1}{3}=\frac{-5}{6}\)

\(x=\frac{-5}{6}+\frac{1}{3}\)

\(x=\frac{-1}{2}\)

Answer 3

Ta có:

\(\left|x-\frac{1}{3}\right|=\frac{5}{6}\)

Ta có 2 trường hợp:

\(\Rightarrow x-\frac{1}{3}=\frac{5}{6}\)               hoặc                      \(x-\frac{1}{3}=-\frac{5}{6}\)

\(\Rightarrow x=\frac{5}{6}+\frac{1}{3}\)                                            \(x=-\frac{5}{6}+\frac{1}{3}\)

\(\Rightarrow x=\frac{7}{6}\)                                                       \(x=-\frac{1}{2}\)

Vậy \(x\in\left\{\frac{7}{6};-\frac{1}{2}\right\}\)