=> \(\frac{1}{7x+2}=\frac{1}{9}\)
=> 7x + 2 = 9
=> 7x = 7
=> x = 1
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Tim x;
\(3^{x-1}+5\times3^{x-1}=162\)
Cac ban vui long giai day du giup minh!
\(\left(0,25\right)^4\times1024\)
Cac ban vui long giai day du giup minh. Thanks truoc
tim da thuc B biet:
\(B-\left(3x^6-4xy^5+\frac{1}{3}xy^2-\frac{3}{2}\right)=\left(7x^6-\frac{1}{2}xy^5-xy^2-\frac{1}{3}\right)\)
giup mk nha cac bn , ai co cach giai ro rang mk se tick 3 cai
\(\left[-\frac{2}{5}x^3.\left(2x-1\right)^m+\frac{2}{5}x^{m+3}\right]:\left(-\frac{2}{5}x^3\right)\)
tim x nguyen
giai ra giup minh voi
Tính A=\(\frac{2^{12}.3^5-4^6.4^2}{\left(2^2.3\right)^6+8^4.8^5}=\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^3.14^3}\)
cac ban giup minh nha. minh the neu ai giup minh se like cho nguoi ay 100 luon. the day
tim GTNN
\(A=x^2-3x+5\)
\(B=\left(2x-1\right)^2+\left(x+2\right)^2\)
cac ban giup mk voi
/x-1/+/(x-1)(x+1)/=0
tim x
giai giup minh coi cac ban
cam on
Tim gia tri nho nhat
A=/x-2010/+/x-2011/
B=/x-1/+/x-2/+/x-3/+2011
C=5\(x^2\)+20x+2010
cac ban giai va cach trinh bay nhe
minh kich dung cho
giai giup minh voi
-x^3-2x^2+7-(-3x^4+x^3+10x^2-7=?
giai day du cho to nhe to se tick cho cam on cac ban nhiu