(2x-3)( 3/4x+1) = 0
=> 2x-3= 0 hoặc 3/4x +1 = 0
=> 2x= 3 hoặc 3/4x = -1
=> x=3/2 hoặc x= -4/3
(5x-1)(2x-1/3) = 0
=> 5x-1 = 0 hoặc 2x-1/3 = 0
5x =1 hoặc 2x=1/3
x=1/5 hoặc x= 1/6
\(9.\left(\frac{-1}{3}\right)^3x-3.\left(\frac{-1}{3}\right)^2x+\left(\frac{-1}{3}\right)x+1=0\)
tìm x
\(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0\)
\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\left(2x+\frac{3}{5}\right)^{^2}-\frac{9}{25}=0\)
\(3\left(3x-\frac{1}{2}\right)+\frac{1}{9}=0\)
tìm x
a) \(\frac{x-1}{2}+\frac{x-2}{5}=\frac{1}{4}+\frac{x-7}{10}\)
b) \(3-\frac{2}{2x-3}=\frac{2}{5}+\frac{1}{2x-3}-\frac{3}{2}\)
c)\(7\cdot\left(x-1\right)+2x\cdot\left(1-x\right)=0\)
d) \(\frac{x+1}{2008}+\frac{x+2}{2017}+\frac{x+3}{2016}=\frac{x+10}{2009}+\frac{x+11}{2008}+\frac{x+12}{2007}\)
e) \(\frac{2}{\left(x-1\right)\cdot\left(x-3\right)}+\frac{5}{\left(x-3\right)\cdot\left(x-8\right)}+\frac{12}{\left(x-8\right)\cdot\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
Tìm x
a,\(\frac{1}{3}x+\frac{2}{5}\left\{x-1\right\}=0\)
b, \(\left\{2x-3\right\}\left\{6-2x\right\}=0\)
Tìm x
a) \(\left(x+1\right)-\frac{x+1}{3}=\frac{5\left(x+1\right)-1}{6}\)
b) \(\left(1-x\right)^2+\left(x+2\right)^2=2x\left(x-3\right)-7\)
c) \(2+\frac{x-2}{2}-\frac{2x-4}{3}-\frac{5}{6}\left(2-x\right)=0\)
Tìm x
\(\left(2x+\frac{3}{5}\right)^2-\frac{9}{25}=0\)
\(3\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
giải nhanh hộ mình với, mai mình nộp rồi
Tìm x
a) \(\left(x-1\right)+\left(x-2\right)+\left(x-3\right)+.....+\left(x-100\right)=101\)
b) \(x+2x+3x+....+100x=1000\)
c) \(x+1+2\left(x+2\right)+3\left(x+3\right)+...+100\left(x+100\right)=101^2\)
d) \(\frac{1+x}{1}+\frac{1+x}{2}+\frac{1+x}{3}+...+\frac{1+x}{30}=0\)
e) \(\left(1+\frac{x}{1}\right)\left(2-\frac{x}{2}\right)\left(3-\frac{x}{3}\right)=0\)
BẠN NÀO BIẾT PHẦN NÀO THÌ GIÚP MIK NHÉ!
Thank!!
Bài 1 : Tìm x, biết: (\(\left(2x+\frac{1}{2}\right).\left(\frac{3}{4}-x\right)=0\)
Tìm x biết:
\(\left(2x+\frac{1}{3}\right)\left(\frac{3}{4}x-6\right)-\left(3x-\frac{2}{3}\right)\left(\frac{1}{2}x-\frac{6}{9}\right)=1\)
