a) x = 8
Vì khi cơ số là 0 thì có mũ mấy lên bao nhiêu cũng = 0
=>( 2.8-16)^8-(2.8-16)^3=(16-16)^8-(16-16)^3=0^8-0^3=0-0=0
b) x = 2
Vì khi cơ số =1 thì mũ lên bao nhiêu cũng =1
Mỏi tay quá , chắc đến đây đã hiểu rồi tự làm nha ! Nhớ ks nhé !
Tìm x biết:
f)\(32^{-x}.16^x=1024;\left(x\in N\right)\) g)\(3^{x-1}+5.3^{x-1}=162;\left(x\in N\right)\)
h)\(\left(2x-1\right)^6=\left(2x-1\right)^8\) i)\(5^x+5^{x+2}=650;\left(x\in N\right)\)
Tìm x:
a) \(\dfrac{1}{3}.x+\dfrac{2}{5}\left(x-1\right)=0\)
b)\(-5.\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}.\left(x-\dfrac{2}{3}\right)=x\)
c)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
d)\(9.\left(3x+1\right)^2=16\)
Tìm x biết:
\(a,\left(x-\dfrac{3}{4}\right)+50\%=\dfrac{1}{6}\)
\(b,\dfrac{1}{2}x-\dfrac{5}{6}x=\dfrac{7}{2}\)
\(c,\left(4-x\right)\left(3x+5\right)=0\)
\(d,\dfrac{x}{16}=\dfrac{50}{32}\)
\(e,\left(2x-3\right)+\dfrac{3}{2}=-\dfrac{1}{4}\)
tìm x , biết
\(a,\left|2x-3\right|-\left|3x+2\right|=0\\ b,\left|\dfrac{1}{2}x\right|=3-2x\)
Tìm x \(\in Z\)
a,\(\left|2x-1\right|=\left|x+3\right|\)
b,\(\left(x^2-1\right)\left(x^2-20\right)\le0\)
c, \(\left(x+1\right)+\left(x+3\right)+\left(x+5\right)+...+\left(x+2015\right)=0\)
d, \(\left(x-3\right)+\left(x-2\right)+\left(x-1\right)+...+10+11=11\)
Tìm x, biết:
\(a,\dfrac{1}{3}:\left(2x-1\right)=\dfrac{-1}{6}\)
\(b,\left(3x+2\right)\left(\dfrac{-2}{5}x-7\right)=0\)
\(c,\dfrac{x}{8}=\dfrac{9}{4}\)
\(d,\dfrac{x-3}{2}=\dfrac{18}{x-3}\)
\(e,4,5x-6,2x=6,12\)
\(h,11,4-\left(x-3,4\right)=-16,2\)
a) \(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16\frac{2}{3}\right)=0\)0
b) \(\left(\frac{x}{3}-5\frac{1}{4}\right)^2-\frac{-2}{5}=1\frac{1}{25}\)
c) \(1\frac{1}{3}-25\%\left(x-\frac{8}{3}\right)+2x=1,6:\frac{3}{5}\)
1)Tìm x biết :
a) \(\left(2x+1\right)^3=125\); b)\(\left(4x-1\right)^2=25.9\);c)\(2^x+2^x+3=144\);d)\(3^{2x+2}=9^{x+3}\);e)\(x^{15}=x^2\)
Thực hiện phép tính:
a)\(\left(3.4.2^{16}\right)^2:\left(11.2^{13}.4^{11}-16^9\right)\)
b)1+2-3-4+5+6-7-8+............-299-300+301+302
Tìm x biết:
a)\(\frac{2}{3}.\left(x-\frac{3}{8}\right)-x-\left(-\frac{7}{8}+\frac{2}{3}\right)=\left(\frac{-3}{4}\right)^3:1\frac{11}{16}\)
b)\(-\frac{7}{8}+\frac{7}{8}:\left(\frac{2}{3}-x\right)+\frac{5}{6}:\left(-1\frac{11}{35}\right)=\left(0,8\right)^2\)
