Các câu hỏi tương tự
tim x biet
\(2\frac{1}{3}-\frac{1}{6}\left|-2x+\frac{1}{2}\right|\)\(=\frac{1}{2}\left|-x+\frac{1}{2}\right|-\frac{2}{3}\)
Tìm x là số tự nhiên biết:
\(2x:\left(1+\frac{1}{1+2}+\frac{1}{1+2+3}+...+\frac{1}{1+2+3+...+x}\right)=2020\)
a) \(\left(\frac{6^3-10,5^3}{6^2.3^3-15^2.5^2}.\left|x-2\right|\right):10=\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).....\left(1-\frac{1}{9}\right).\left(1-\frac{1}{10}\right)\)
b) \(\frac{x-2018}{2}+\frac{x-2020}{4}=\frac{x-2040}{8}+\frac{x-2030}{14}\)
Bai 1:a)Tim x biet\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\times\left(x+1\right)}=\frac{2009}{2011}\)
b)\(\left(x-1\right)\times f\left(x\right)=\left(x+4\right)\times f\left(x\right)\)voi moi x
Bai 2;Tim x;y;z biet a)\(\frac{y+z+1}{x}=\frac{x+z+2}{y}=\frac{x+y-3}{z}\) b)\(\frac{2x+1}{5}=\frac{3y-z}{7}=\frac{2x+3y-1}{6x}\)
Tim x,y,z biet
2/x-1/+/2x+5/=\(\frac{14}{2+\left(3-2y\right)^{2020}}\)
Cho hàm số f(x)\(=\frac{x}{2^x}\).Tìm \(x\inℕ^∗\)biết \(f\left(1\right)+f\left(2\right)+f\left(3\right)+...+f\left(x\right)=\frac{2^{x+1}-x}{2^x}-\frac{1}{512}\)
Bài 1: Tìm \(n\inℕ^∗\)
biết : \(2n:\left(1+\frac{1}{1+2}+\frac{1}{1+2+3}+.....+\frac{1}{1+2+...+n}\right)=2020\)
1 Thực hiện phép tính :a)2frac{1}{5}.frac{25}{4}-10frac{1}{5}.frac{24}{5}b)5.(frac{-2}{5})^2+2.left(frac{-2}{5}right)+4.left(frac{-2}{5}right)^0c)sqrt{frac{16}{9}+}left(frac{2}{3}right)^9:left(frac{-2}{3}right)^8-/-2020/2. tìm x,y,z biết :a)backslash-2x+frac{1}{3}backslash-frac{1}{3}2frac{2}{3}b) frac{x-1}{x-5}frac{6}{7}c) 2x3y5z và x+y-z95
Đọc tiếp
1 Thực hiện phép tính :
a)\(2\frac{1}{5}.\frac{25}{4}-10\frac{1}{5}.\frac{24}{5}\)
b)\(5.(\frac{-2}{5})^2+2.\left(\frac{-2}{5}\right)+4.\left(\frac{-2}{5}\right)^0\)
c)\(\sqrt{\frac{16}{9}+}\left(\frac{2}{3}\right)^9:\left(\frac{-2}{3}\right)^8-/-2020/\)
2. tìm x,y,z biết :
a)\(\backslash-2x+\frac{1}{3}\backslash-\frac{1}{3}=2\frac{2}{3}\)
b) \(\frac{x-1}{x-5}=\frac{6}{7}\)
c) 2x=3y=5z và x+y-z=95
Tim so huu ti x
a)\(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}-2\right)\))
b)\(\frac{1}{x-1}+\frac{-2}{3}\left(\frac{3}{4}-\frac{6}{5}\right)=\frac{5}{2-2x}\)
c)\(3-\frac{2}{2x-3}=\frac{2}{5}+\frac{2}{9-6x}-\frac{3}{2}\)
e)\(\frac{x}{2}-\frac{1}{x}=\frac{1}{12}\)