|4-x|+2x=3
<=>|4-x|=3-2x=-2x+3<=>\(\int^{4-x=-2x+3}_{4-x=-\left(-2x+3\right)=2x-3}\)
TH1: 4-x=-2x+3<=>x=-1
TH2:4-x=2x-3<=>x=7/3
Vậy.....
Chia ra 2 trường hợp :
+ Nếu x < 4
+ Nếu x >= 4
|4-x|+2x=3
<=>|4-x|=3-2x=-2x+3<=>\(\int^{4-x=-2x+3}_{4-x=-\left(-2x+3\right)=2x-3}\)
TH1: 4-x=-2x+3<=>x=-1
TH2:4-x=2x-3<=>x=7/3
Vậy.....
Chia ra 2 trường hợp :
+ Nếu x < 4
+ Nếu x >= 4
tim x :
a) I x+1I+I x -2I+I x+3I = 6
b) 2Ix+2I+I4-xi= 11
c) IxI - I 2x+3I = x-1
tim x :
a) I x+1I+I x -2I+I x+3I = 6
b) 2Ix+2I+I4-xi= 11
c) IxI - I 2x+3I = x-1
tim x :
a) I x+1I+I x -2I+I x+3I = 6
b) 2Ix+2I+I4-xi= 11
c) IxI - I 2x+3I = x-1
tìm x: I 4-xI + 2x = 3
các bn giúp mk
Tìm x
Ix-3I+I1-xI=x+5
Ix-4I+I3-xI=1-2x
tim x biet :
a) ( 2x^2+4 ) - (x^2-3/2 ) = (-3+4x^2)+ ( -4x^2/3+1)
b) ( I xI -4) - ( 2- I-xI ) = 1/3 . I xI -5
Tìm x biết:
a,I5-xI+Ix-5I+I10-2xI=7
b,Ix+1I+IxI=4x-2012
c,I5+2xI\(\le\)7
d,I4-7xI>3
e,I2-2xI-3-3x<-4
f,2<IxI<6
g,(x-1)(3-2x)>0
h,x(x+1)(3-x)\(\le\)0
i,\(\frac{5-x}{3+x}\)\(\ge\)0
j,\(\frac{1+3x}{3-x}\) có giá trị không dương
tim x biet :
a) ( 2x2+4 ) - (x2-3/2 ) = (-3+4x2)+ ( -4x2/3+1)
b) ( I xI -4) - ( 2- I-xI ) = 1/3 . I xI -5
tim x biet :
a) ( 2x2+4 ) - (x2-3/2 ) = (-3+4x2)+ ( -4x2/3+1)
b) ( I xI -4) - ( 2- I-xI ) = 1/3 . I xI -5