\(\frac{x}{50}+\frac{x-1}{49}+\frac{x-2}{48}+\frac{x-3}{47}+\frac{x-150}{25}=0\)
\(\Leftrightarrow\)\(\frac{x}{50}-1+\frac{x-1}{49}-1+\frac{x-2}{48}-1+\frac{x-3}{47}-1+\frac{x-150}{25}+4=0\)
\(\Leftrightarrow\)\(\frac{x-50}{50}+\frac{x-50}{49}+\frac{x-50}{48}+\frac{x-50}{47}+\frac{x-50}{25}=0\)
\(\Leftrightarrow\)\(\left(x-50\right)\left(\frac{1}{50}+\frac{1}{49}+\frac{1}{48}+\frac{1}{47}+\frac{1}{25}\right)=0\)
\(\Leftrightarrow\)\(x-50=0\) (vì 1/50 + 1/49 + 1/48 + 1/47 + 1/25 > 0 )
\(\Leftrightarrow\)\(x=50\)
Vậy....