Question

tìm x

\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{4}{3}=\frac{1}{2}-\frac{6}{5}\)

Answer 1

\(\Rightarrow x\left(\frac{4}{5}-1-\frac{3}{2}\right)+\frac{4}{3}=\frac{-7}{10}\)

\(\Rightarrow x\cdot\frac{-17}{10}=\frac{-61}{30}\)

\(\Rightarrow x=\frac{61}{51}\)

vậy_

Answer 2

Ta có:\(\frac{4}{5}\)x - x - \(\frac{3}{2}\)x  + \(\frac{4}{3}\)=\(\frac{1}{2}\)-\(\frac{6}{5}\)

=>x.(\(\frac{4}{5}\)-1-\(\frac{3}{2}\))=\(\frac{-7}{10}\)-\(\frac{4}{3}\)

=>x.\(\frac{-17}{10}\)=\(\frac{-61}{30}\)

=>x=\(\frac{-61}{30}\):\(\frac{-17}{10}\)=\(\frac{61}{51}\)

Answer 3

\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{4}{3}=\frac{1}{2}-\frac{6}{5}\)

=> \(x.\left(\frac{4}{5}-1-\frac{3}{2}\right)+\frac{4}{3}=\frac{-7}{10}\)

=> \(x.\frac{-17}{10}+\frac{4}{3}=\frac{-7}{10}\)

=> \(x.\frac{-17}{10}=\frac{-61}{30}\)

=> \(x=\frac{-61}{30}:\frac{-17}{10}=\frac{61}{51}\)