\(\frac{4}{3}+x.\frac{2}{3}-\frac{1}{4}=\frac{53}{12}\)
\(x.\frac{2}{3}-\frac{1}{4}=\frac{53}{12}-\frac{4}{3}\)
\(x.\frac{2}{3}-\frac{1}{4}=\frac{37}{12}\)
\(x.\frac{2}{3}=\frac{37}{12}+\frac{1}{4}\)
\(x.\frac{2}{3}=\frac{10}{3}\)
\(x=\frac{10}{3}:\frac{2}{3}\)
\(x=\frac{30}{6}=5\)
Vậy x = 5
mik ko chắc
\(\frac{4}{3}+x.\frac{2}{3}-\frac{1}{4}=4\frac{5}{12}\)
\(\frac{4}{3}+x.\frac{2}{3}=4\frac{5}{12}+\frac{1}{4}\)
\(\frac{4}{3}+x.\frac{2}{3}=\frac{53}{12}+\frac{1}{4}\)
\(\frac{4}{3}+x.\frac{2}{3}=\frac{14}{3}\)
\(x.\frac{2}{3}=\frac{14}{3}-\frac{4}{3}\)
\(x.\frac{2}{3}=\frac{10}{3}\)
\(x=\frac{10}{3}:\frac{2}{3}\)
\(x=5\)
\(\frac{4}{3}+x\cdot\frac{2}{3}-\frac{1}{4}=4\frac{5}{12}\)
\(\frac{2}{3}\cdot2+x\cdot\frac{2}{3}-\frac{1}{4}=\frac{53}{12}\)
\(\frac{2}{3}\cdot2+x\cdot\frac{2}{3}=\frac{53}{12}+\frac{1}{4}\)
\(\frac{2}{3}\cdot2+x\cdot\frac{2}{3}=\frac{56}{12}\)
\(\frac{2}{3}\cdot\left(x+2\right)=\frac{56}{12}\)
\(x+2=\frac{56}{12}\div\frac{2}{3}\)
\(x+2=7\)
\(x=7-2=5\)
