x^2 - 4x + 4 = 5 ( x - 2 )
x^2 - 4x + 4 - 5 ( x - 2 ) = 0
( x - 2 ) ^2 - 5 ( x - 2 ) = 0
( x - 2 ) ( x - 2 - 5 ) = 0
( x - 2 ) ( x - 7 ) = 0
x - 2 = 0 hoặc x - 7 = 0
x = 2 hoặc x = 7
c) (x-2)^2=5(x-2)
=> x-2=5 hoặc x-2 =0
=> x=7 hoặc x=2
d) (2x-3)^2=(5-x)^2
=> 2x-3=5-x
=> x=8/3
4x^2 - 12x + 9 = ( 5 - x ) ^2
( 2x - 3 ) ^2 = ( 5 - x ) ^2
( 2x - 3 ) ^2 - ( 5 - x ) ^2 = 0
( 2x - 3 - 5 + x ) ( 2x - 3 + 5 - x ) = 0
( 3x - 8 ) ( x + 2 ) = 0
3x - 8 = 0 hoặc x + 2 = 0
x = 8/3 hoặc x = -2
\(c.x^2-4x+4=5\left(x-2\right).\)
\(\Leftrightarrow x^2-4x+4=5x-10\)
\(\Leftrightarrow x^2-9x+14=0\)
\(\Leftrightarrow\left(x-2\right)\left(x-7\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x-7=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=7\end{cases}}}\)
\(d.4x^2-12x+9=\left(5-x\right)^2\)
\(\Leftrightarrow\left(2x-3\right)^2=\left(5-x\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}2x-3=5-x\\2x-3=x-5\end{cases}}\Leftrightarrow\orbr{\begin{cases}3x=8\\x=-2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{-8}{3}\\-2\end{cases}}\)
Ps: k cho tớ nhé !
# Aeri #
