Question

tim x,biet

x(x-2)-3(x+1)=x(x-6)

Answer 1

x(x-2)-3(x+1)=x(x-6)

=>x²-2x-3x-3=x²-6x

=>x²-2x-3x-3-x²+6x=0

=>(x²-x²)+(-2x-3x+6x)-3=0

=>0+x-3=0

=>x=3

Answer 2

x(x-2)-3(x+1)=x(x-6)

=>x²-2x-3x-1=x²-6x

=>x²-2x-3x-1-x²+6x=0

=>(x²-x²)+(-2x-3x+6x)-1=0

=>0+x-1=0

=>x=1

Answer 3

x(x-2)-3(x+1)=x(x-6)

=>x²-2x-3x-3=x²-6x

=>x²-2x-3x-3-x²+6x=0

=>(x²-x²)+(-2x-3x+6x)-3=0

=>0+x-3=0

=>x=3