\(3^x+3^{x+1}+3^{x+2}=1053\)
\(3^x+3^x.3+3^x.3^2=1053\)
\(3^x.\left(1+3+9\right)=1053\)
\(3^x.13=1053\)
\(3^x=1053:13\)
\(3^x=81\)
\(3^x=3^4\)
\(\Rightarrow x=4\)
Ta có :
\(3^x+3^{x+1}+3^{x+2}=1053\)
\(\Rightarrow3^x\left(1+3^1+3^2\right)=1053\)
\(\Rightarrow3^x\left(1+3+9\right)=1053\)
\(\Rightarrow3^x.13=1053\)
\(\Rightarrow3^x=1053:13=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
Ta có:
\(3^x+3^{x+1}+3^{x+2}=1053\)
\(\Rightarrow3^{x+\left(x+1\right)+\left(x+2\right)}=1053\)
\(\Rightarrow3^{3x+3}=1053\)
\(\Rightarrow27^x.3^3=1053\)
\(\Rightarrow27^x.27=1053\)
\(\Rightarrow27^x=1053:27\)
\(\Rightarrow27^x=39\)
Xin lỗi,nhưng bạn viết sai đề rồi
