Question

tìm x,biết

(3x-5)(x+1)-(3x-1)(x-1)=x-4

Answer 1

`(3x-5)(x+1)-(3x-1)(x-1)=x-4`

`<=>(3x^2 -5x+3x-5)-(3x^2 -x-3x+1)-x+4=0`

`<=>(3x^2 -2x-5)-(3x^2 -4x+1)-x+4=0`

`<=>3x^2 -2x-5-3x^2 +4x-1-x+4=0`

`<=>x-2=0`

`<=>x=2`

Vậy `S={2}`

Answer 2

Answer 3

`=> 3x^2 -2x - 5 - 3x^2 + 4x -1 - x + 4 = 0`

`=> x - 2 = 0`

`=> x = 2`.

Answer 4