Question

Tìm x,biết:
1/7x+(3/5x-0,75x)=-1/35

Answer 1

\(\dfrac{1}{7}x+\left(\dfrac{3}{5}x-0,75x\right)=-\dfrac{1}{35}\)

\(\dfrac{1}{7}x+\left(\dfrac{3}{5}x-\dfrac{3}{4}x\right)=-\dfrac{1}{35}\)

\(\dfrac{1}{7}x-\left(-\dfrac{3}{20}x\right)=-\dfrac{1}{35}\)

\(\dfrac{41}{140}x=-\dfrac{1}{35}\)

\(x=-\dfrac{4}{41}\)