Question

Tìm x,biết: (x\(^2\)-2)\(^5\)=1

Answer 1

`@` `\text {Ans}`

`\downarrow`

`(x^2-2)^5 = 1`

`=> (x^2-2)^5 = 1^5`

`=> x^2-2=1`

`=> x^2 = 1+2`

`=> x^2=3`

`=> x = +-\sqrt {3}`

Vậy, `x \in +-\sqrt {3}.`

Answer 2

\(\Leftrightarrow x^2-2=\sqrt[5]{1}=1\\ \Leftrightarrow x^2=1+2=3\\ \Rightarrow x=\pm\sqrt{3}\)