Ta có: \(\left(x-3\right)^2=25\)
\(\Leftrightarrow\left(x-3\right)^2=5^2\left(x\inℕ^∗\right)\)
\(\Leftrightarrow x-3=5\)
\(\Leftrightarrow x=5+3\)
\(\Leftrightarrow x=8\)
hok tốt!!
(x-3)2 = 25
(x-3)2 = 52
x-3 = 5
x= 5+3
x=8
\(\left(x-3\right)^2=25\)
\(\Leftrightarrow\left(x-3\right)^2=5^2\)
\(\Leftrightarrow x-3=5\)
\(\Leftrightarrow x=5+3\)
\(\Leftrightarrow x=8\)
Vậy x = 8