Câu 1:Tìm x biết:
a,\(0,2\div1\frac{1}{5}=\frac{2}{3}\div\left(6x+7\right)\)
b,\(13\frac{1}{3}\div1\frac{1}{3}=26\div\left(2x-1\right)\)
Câu 2:Tìm x  Z để biểu thức P có giá trị nguyên :
a, P=\(\frac{5}{\sqrt{x-1}}\)
b, P=\(\frac{7}{\sqrt{x-1}}\)
Bài 1 :Tìm x để :
\(\frac{x-2}{x-6}>0\)
Bài 2:Tim x de : \(\frac{3x+9}{x-4}\)nhận giá trị nguyên
Bài 3 : Thực hiện phép tính : \(\frac{1}{2}\div\left(-1\frac{3}{2}\right)\div1\frac{1}{3}\div\left(-1\frac{1}{4}\right)\div1\frac{1}{5}\div...\div1\frac{1}{99}\div\left(-1\frac{1}{100}\right)\)
Giúp mình với nhé. Mình tick cho.thank you
Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
Tìm x biết
\(\frac{x+1}{x-2}=\frac{3}{4}\)
\(\frac{2x-3}{x+1}=\frac{4}{7}\)
Tìm x :
\(\frac{\left(1\times2+2\times3+3\times4+...+98\times99\right)x}{26950}=12\frac{6}{7}:\frac{3}{2}\)
Tìm x biết:
a) x. \(\frac{1}{2}.\frac{2}{3}=4\)
b) \(\frac{-2}{7}.\frac{5}{7}.x=\frac{7}{21}\)
c) \(\left(x-\frac{1}{2}\right).\left(2x-\frac{1}{3}\right)=0\)
d) \(\frac{x+1}{3}+\frac{x+1}{4}+\frac{x+1}{5}=0\)
tìm x, biết
1. \(\frac{x+1}{x-2}=\frac{3}{4}\)
2. \(\frac{52}{2x-1}=\frac{13}{30}\)
3.\(\frac{2x-3}{x+1}=\frac{4}{7}\)
4. \(\frac{2x+3}{42}=\frac{3x-1}{32}\)
Tìm x, biết :
\(a.\frac{7^{x+2}+7^{x+1}+7x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
\(b.\left(4x-3\right)^4=\left(4x-3\right)^2\)
1a)tìm x,y biết: \(4+\frac{x}{7+y}=\frac{4}{7}and:x+y=22\)
b)cho \(\frac{x}{3}=\frac{y}{4}\)và \(\frac{y}{5}=\frac{z}{6}\). Tính M=\(\frac{2x+3y+4z}{3x+4y+5z}\)
c) tìm x biết \(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}...\frac{30}{62}.\frac{31}{64}=2^x\)
d)\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2x\)
2. Tính:P=\(1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+...+\frac{1}{16}\left(1+2+..+16\right)\)