\(\left(2x-1\right)^3=2^9=\left(2^3\right)^3\)
=> 2x-1=23
=> 2x = 23 + 1
=> 2x = 9
=> x = 9/2
(2x-1)3 = 643 <=> 2x-1 = 64
2x = 65 => x = 32,5
Tim xthuoc Z biet:
1,|2x-5|-|2x+9|=0
2,|x+1|-|x+2|-|3-x|=7
3,|2x+3|+|3x+2|-|4-x|=10
27x : 3x = 9
1/2 x 2x + 4 x 2x = 9 x 25
Tim x
Tim x:
a/\(4^{x+3}-248=2^{x+1}\)
b/\(9^{x+2}-54=3^{2x+3}\)
c/\(4^{x-1}+16=2^{2x+1}\)
Tim x biet
(x+1/5)-4=-2
(2x+3)*(x-7)=0
31/9(x)-5/2=8/3
tinh so huu ti x
2/3x-3/12=4/5-(7/x-2)
2x-3/3+-3/2=5-3x/6-1/3
tim x
(x-1).(x-2)>0
2x-3<0
(2x-4).(9-3x)<0
moi nguoi giup minh nhe cam on nhieu
Tim x:
a) 2x-3=1/2
b) /x+1/=0.25
c) 32/2x=2
d) 64/125=(4/5)^x
e) x/6=-9/18
f) -4/x+3=12/-15
g) x+1/2/0.75=3/2/0.25
Tim x biet:
a.2|2x-3|=1/2
b.(x-1)^2=9/16
c.3/5(x-5/6)-1/2(3/2-1)=-1/4
d.1/3+1/6+1/10+......+2/x(x+1)=2015/2016
1)tim x biet rang:
a)3^x-1=1/243
b)2^x+2^x+3=144
c)81^-2x.27x=9^5
2)tim tiep so ghang thu 5 cua day so sau:-1/a^2;2/a^3;-6/a^4;24/a^5;...
3)tim so tu nhien x biet :
a)4^x+4^x+3=4160
b)2^x-1+5.2^x-2=7/32
Tim ngiem cua da thuc M(x) =2x-5)(x^2-9/16)(x^2+1).
