a) x = \(\frac{1}{3}\)
b) x = \(\frac{1}{42}\)
a) Ta có : \(\left(3x-1\right)\left(-\frac{1}{2}x+5\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}3x-1=0\\-\frac{1}{2}x+5=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}3x=1\\-\frac{1}{2}x=-5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{3}\\x=10\end{cases}}\)
Vậy x thuộc {1/3;10}
a) x = \(\frac{1}{3}\)
b) x = \(\frac{1}{42}\)