\(5x\left(6-x\right)+\left(5x-3\right)x=27\)
\(30x-5x^2+5x^2-3x=27\)
\(27x=27\)
\(x=1\)
Vậy \(x=1\)
\(3\left(2x-1\right)-5\left(x-3\right)+6.\left(3x-4\right)=83\)
\(6x-3-5x+15+18x-24=83\)
\(19x-12=83\)
\(19x=95\)
\(x=\frac{95}{19}\)
\(x=5\)
Vậy \(x=5\)
\(5x.\left(6-x\right)+\left(5x-3\right)x=27\)
\(\Rightarrow30x-5x^2+5x^2-3x=27\)
\(\Rightarrow\left(30x-3x\right)-\left(5x^2-5x^2\right)=27\)
\(\Rightarrow27x=27\)
\(\Rightarrow x=\)................................................(XIn lỗi em không biết chia :D)
\(a,5x\left(6-x\right)+\left(5x-3\right)x=27\)
\(\Leftrightarrow30x-5x^2+5x^2-3x=27\)
\(\Leftrightarrow27x=27\)
\(\Leftrightarrow x=1\)
\(b,3\left(2x-1\right)-5\left(x-3\right)+6\left(3x-4\right)=83\)
\(\Leftrightarrow6x-3-5x+15+18x-24=83\)
\(\Leftrightarrow19x-12=83\)
\(\Leftrightarrow19x=95\)
\(\Leftrightarrow x=5\)
