Question

Tìm x:

a) ( x + \(\frac{3}{4}\): 5 = \(\frac{5}{6}\)

b) ( \(\frac{4}{3}\)+ x) x \(\frac{1}{11}\)= \(\frac{7}{11}\)

giúp mik với

 

Answer 1

a) \(\left(x+\frac{3}{4}\right):5=\frac{5}{6}\)

\(x+\frac{3}{4}=\frac{5}{6}\text{x}5\)

\(x+\frac{3}{4}=\frac{25}{6}\)

\(x=\frac{25}{6}-\frac{3}{4}\)

\(x=\frac{41}{12}\)

b) \(\left(\frac{4}{3}+x\right)\text{x}\frac{1}{11}=\frac{7}{11}\)

\(\frac{4}{3}+x=\frac{7}{11}:\frac{1}{11}\)

\(\frac{4}{3}+x=7\)

\(x=7-\frac{4}{3}\)

\(x=\frac{17}{3}\)

Answer 2

a) \(x+\frac{3}{4}\div5=\frac{5}{6}\)

\(x+\frac{3}{4}=\frac{5}{6}\times5\)

\(x+\frac{3}{4}=\frac{25}{6}\)

\(x=\frac{25}{6}-\frac{3}{4}\)

\(x=\frac{41}{21}\)

b) \(\left(\frac{4}{3}+x\right)\times\frac{1}{11}=\frac{7}{11}\)

\(\frac{4}{3}+x=\frac{7}{11}\div\frac{1}{11}\)

\(\frac{4}{3}+x=7\)

\(x=7-\frac{4}{3}\)

\(x=\frac{17}{3}\)

Answer 3

a,(x+\(\frac{3}{4}\)):5=\(\frac{5}{6}\)

x+\(\frac{3}{4}\)=\(\frac{5}{6}\)x 5

x+\(\frac{3}{4}\)=\(\frac{25}{6}\)

x=\(\frac{25}{6}\)-\(\frac{3}{4}\)

x=\(\frac{41}{12}\)