a) x + \(\frac{1}{6}\)=\(-\frac{3}{8}\)
x=\(\frac{-3}{8}-\frac{1}{6}\)
x=\(\frac{-13}{24}\)
b)\(\frac{1}{2}\)x + \(\frac{1}{8}\)x = \(\frac{3}{4}\)
\(\left(\frac{1}{2}+\frac{1}{8}\right)\)x = \(\frac{3}{4}\)
\(\frac{5}{8}\)x = \(\frac{3}{4}\)
x = \(\frac{3}{4}:\frac{5}{8}\)
x =\(\frac{6}{5}\)
c) 2 - l3/4-xl=7/12
l3/4-xl=17/12
nếu 3/4 - x > 0
thì 3/4 - x = 17/12
x= -2/3
nếu 3/4 - x <0
thì 3/4 - x = -17/12
x = 13/6
d) \(\left(2x-4.5\right):\frac{3}{4}-\frac{1}{3}=1\)
\(\left(2x-4.5\right):\frac{3}{4}=\frac{4}{3}\)
\(2x-4.5=1\)
2x = 5.5
x = 2.75
a, x + 1/6 = -3/8
x = -3/8 - 1/6
x = -13/24
b, 1/2x + 1/8x = 3/4
x * (1/2+1/8) = 3/4
x * 5/8 = 3/4
x = 3/4 : 5/8
x = 6/5
c, 2 - |3/4-x| = 7/12
|3/4-x| = 2 - 7/12
|3/4-x| = 17/12
=> 3/4 - x = 17/12 hoặc -17/12
# 3/4 - x = 17/12
=> x = -2/3
# 3/4 - x = -17/12
=> x = 13/6
=> x = { -2/3 ; 13/6}
d, (2x - 4,5) : 3/4 -1/3 = 1
(2x - 4,5) : 3/4 = 1 + 1/3
(2x - 4,5 ) : 3/4 = 4/3
2x - 4,5 = 4/3 * 3/4
2x - 4,5 = 1
2x = 1 + 4,5
2x = 5,5
x = 5,5 : 2
x = 2,75
a) \(x+\frac{1}{6}=-\frac{3}{8}\) c) \(2-\left|\frac{3}{4}-x\right|=\frac{7}{12}\)
<=> \(x=-\left(\frac{3}{8}+\frac{1}{6}\right)\) <=> \(\left|\frac{3}{4}-x\right|=2-\frac{7}{12}\)
<=> \(x=-\left(\frac{9}{24}+\frac{4}{24}\right)\) <=> \(\left|\frac{3}{4}-x\right|=\frac{24}{12}-\frac{7}{12}\)
<=> \(x=-\frac{13}{4}=-3\frac{1}{4}\) <=> \(\left|\frac{3}{4}-x\right|=\frac{17}{12}\)
Vậy: \(x=-3\frac{1}{4}\) => Có hai trường hợp:
b) \(\frac{1}{2}x+\frac{1}{8}x=\frac{3}{4}\) TH1: \(\frac{3}{4}-x=-\frac{17}{12}\) TH2: \(\frac{3}{4}-x=\frac{17}{12}\)
<=> \(\left(\frac{4}{8}+\frac{1}{8}\right)x=\frac{3}{4}\) <=> \(x=\frac{3}{4}+\frac{17}{12}\) <=> \(x=\frac{3}{4}-\frac{17}{12}\)
<=> \(\frac{5}{8}x=\frac{3}{4}\) <=> \(x=\frac{9}{12}+\frac{17}{12}\) <=> \(x=\frac{9}{12}-\frac{17}{12}\)
<=> \(x=\frac{3}{4}:\frac{5}{8}\) <=> \(x=\frac{26}{12}=2\frac{2}{12}\) <=> \(x=-\frac{8}{12}\)
<=> \(x=\frac{3}{4}\cdot\frac{8}{5}\) Vậy: \(x\in\left\{2\frac{2}{12};-\frac{8}{12}\right\}\)
<=> \(x=\frac{6}{5}=1\frac{1}{5}\) d) \(\left(2x-4,5\right):\frac{3}{4}-\frac{1}{3}=1\)
Vậy: \(x=1\frac{1}{5}\) <=> \(\left(2x-4,5\right):\frac{3}{4}=1+\frac{1}{3}\)
<=> \(\left(2x-4,5\right):\frac{3}{4}=\frac{3}{3}+\frac{1}{3}\)
<=> \(\left(2x-4,5\right):\frac{3}{4}=\frac{4}{3}\)
<=> \(2x-4,5=\frac{4}{3}\cdot\frac{3}{4}\)
<=> \(2x-4,5=1\)
<=> \(2x=1+4,5\)
<=> \(2x=5,5=\frac{11}{2}\)
<=> \(x=\frac{11}{2}:2\)
<=> \(x=\frac{11}{2}\cdot\frac{1}{2}\)
<=> \(x=\frac{11}{4}=2\frac{3}{4}\)
Vậy: \(x=2\frac{3}{4}\)
