a) \(x+\frac{2}{3}=\frac{3}{4}-\frac{1}{6}\)
\(x+\frac{2}{3}=\frac{7}{12}\)
\(x=\frac{7}{12}-\frac{2}{3}\)
\(x=-\frac{1}{12}\)
b) \(\left|2x+3\right|=5\)
\(2x=5-3\)
\(2x=2\)
\(x=2:2\)
\(\Rightarrow\left|x\right|=-1,1\)
x+\(\frac{2}{3}\)=\(\frac{7}{12}\)
x =\(\frac{7}{12}\)_\(\frac{2}{3}\)
x =_\(\frac{1}{12}\)
k m nha
b) |2x+3| = 5
=> có 2 trường hợp
TH1 : |2x+3|=5
|2x| = 5-3
|2x|=2
|x|= 2:2
|x| = 1
TH2 : |2x+3|=-5
|2x|=-5-3
|2x|=-8
|x|= -8:2
|x| = -4