a) x + 12 = (-5) - x
=> chuyển vế : x + x = -12 - 5
=> 2x = -17
=> x = \(-\frac{17}{2}\)
b) 2 . (x - 1) + 3 . (x-2) = x - 4
=> 2x - 2 + 3x - 6 = x - 4
=> chuyển vế: 2x +3x - x = 2 + 6 - 4
=> 4x = 4 => x = 1
c) 4 . (2x +7) - 3 . (3x-2) = 24
=> 8x + 28 - 9x +6 = 24
=> - x = -28 - 6 + 24
=> x = 10
d) 3 . ( x-2) + 2x = 10 (Ý bạn c là x đúng không?)
=> 3x - 6 + 2x = 10
=> 5x = 6 + 10
=> 5x = 16 => x = \(\frac{16}{5}\)
Đúng thì k mik nha. Thanks!
\(a,x+12=\left(-5\right)-x\)
\(x+x=12-5\)
\(2x=7\Leftrightarrow x=\frac{7}{2}\)
\(b,2\left(x-1\right)+3\left(x-2\right)=x-4\)
\(2x-2+3x-6=x-4\)
\(2x+3x-x=-4+2+6\)
\(4x=4\Leftrightarrow x=1\)
\(c,4\left(2x+7\right)-3\left(3x-2\right)=24\)
\(4x+28-9x+6=24\)
\(4x-9x=24-28-6\)
\(-5x=-10\Leftrightarrow x=2\)
\(d,3\left(x-2\right)+2x=10\)
\(3x-6+2x=10\)
\(3x+2x=10+6\)
\(5x=16\Leftrightarrow x=\frac{16}{5}\)
a,\(x+12=\left(-5\right)-x\)
\(=>x+x=-5-12=-17\)
\(=>x=\frac{-17}{2}\)
b,\(2.\left(x-1\right)+3.\left(x-2\right)=x-4\)
\(=>2x-2+3x-6=x-4\)
\(=>2x+3x-x=-4+2+6\)
\(=>4x=4\)
\(=>x=1\)
c,