Question

Tìm x

a) \(\left(19.x+2.5^1\right):14=\left(13-8\right)^2-4^2\)

b) \(-\left(x+84\right)+213=-16\)

Answer 1

\(\left(19x+2.5^1\right):14=\left(13-8\right)^2-4^2.\)

\(\left(19x+10\right):14=5^2-4^2\)

\(\left(19x:4\right)+\left(10:4\right)=25-16\)

\(\left(19x:4\right)+\frac{5}{2}=9\)

\(19x:4=9-\frac{5}{2}\)

\(19x:4=\frac{13}{2}\)

\(19x=\frac{13}{2}.4=26\)

\(x=\frac{26}{19}\)

Answer 2

B/ \(-\left(x+84\right)+213=\left(-16\right).\)

\(-x-84+213=-16\)

\(-x+129=-16\)

\(-x=\left(-145\right)\)

\(\Rightarrow x=145\)