a) <=>5x-x=57+7
<=> 4x=64
<=> x=16
b) <=>4x=28+12
<=> x=40/4
<=>10
c) th1 x=0
th2 x-3=0
<=>x=3
d) th1 2x-4=0
<=> x=2
th2 x+1=0
<=> x=-1
câu e mình ko biết làm hihi
a, 5x - 7 = x + 57
5x - x = 57 + 7
4x = 64
x = 64 : 4
x = 16
b, x + 3x - 12 = 28
4x = 28 + 12
4x = 40
x = 10
c, x(x-3) = 0
\(\Rightarrow\orbr{\begin{cases}x=0\\x-3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=3\end{cases}}}\)
d, (2x-4)(x+1)=0
\(\Rightarrow\orbr{\begin{cases}2x-4=0\\x+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=-1\end{cases}}}\)
e, 1+2+...+x=120
=> \(\frac{x\left(x+1\right)}{2}=120\)
=> x(x+1) = 120.2
=>x(x+1) = 240
=> x(x+1) = 15.16
=> x=16