Question

tìm x

a/ 3x(12x-5)-6x(6x-5)=0

b/ x²-8x+6=0

thank trước nha

Answer 1

a/ 3x(12x-5)-6x(6x-5)=0

<=>36x²-15x-36x²+30x=0

<=>15x=0

<=>x=0

b/ x²-8x+6=0

Nghiệm lẻ xem lại câu b

  

Answer 2

a) \(3x\left(12x-5\right)-6x\left(6x-5\right)=0\)

\(\Rightarrow36x^2-15x-36x^2+30x=0\)

\(\Rightarrow15x=0\)

\(\Rightarrow x=0\)

b) \(x^2-8x+6=0\)

\(\Rightarrow x^2-8x+16-10=0\)

\(\Rightarrow x^2-8x+4^2=10\)

\(\Rightarrow\left(x-4\right)^2=10\)

\(\Rightarrow x-4=\sqrt{10}\)

\(\Rightarrow x=4+\sqrt{10}\)