Question

Tìm X

a, 3/5 + X = 1/2 + 1             b, 3 : X = 2/3 + 2\(\dfrac{1}{2}\)

Answer 1

a) \(\dfrac{3}{5}+x=\dfrac{1}{2}+1\)

    \(\dfrac{3}{5}+x=\dfrac{3}{2}\)

            \(x=\dfrac{3}{2}-\dfrac{3}{5}\)

            \(x=\dfrac{15}{10}-\dfrac{6}{10}\)

           \(x=\dfrac{9}{10}\)

b) \(3:x=\dfrac{2}{3}+2\dfrac{1}{2}\)

    \(3:x=\dfrac{2}{3}+\dfrac{5}{2}\)

    \(3:x=\dfrac{4}{6}+\dfrac{15}{6}\)

    \(3:x=\dfrac{19}{6}\)

         \(x=3:\dfrac{19}{6}\) 

         \(x=3\times\dfrac{6}{19}\)

         \(x=\dfrac{18}{19}\)

Mik nhớ câu này làm rồi mak!!!

Answer 2

a,\(\dfrac{3}{5}\)+ x=\(\dfrac{1}{2}\)+1

\(\dfrac{3}{5}\)+x=\(\dfrac{3}{2}\)

x=\(\dfrac{3}{2}\)-\(\dfrac{3}{5}\)

x=\(\dfrac{9}{10}\)

b,

b) 3:x=23+2123:x=23+212

    3:x=23+523:x=23+52

    3:x=46+1563:x=46+156

    3:x=1963:x=196

         x=3:196x=3:196 

         x=3×619x=3×619

         x=1819

Answer 3

a) \(\dfrac{3}{5}+x=\dfrac{1}{3}+2\)

    \(\dfrac{3}{5}+x=\dfrac{1}{3}+\dfrac{2}{1}\)

            \(\dfrac{3}{5}+x=\dfrac{1}{3}+\dfrac{6}{3}\)

            \(\dfrac{3}{5}+x=\dfrac{7}{3}\)

            \(x=\dfrac{7}{3}-\dfrac{3}{5}\)

            \(x=\dfrac{35}{15}-\dfrac{9}{15}\)

            \(x=\dfrac{26}{15}\)