Question

tim x:

a, 3(2x+3)(3x-5)<0

b, 2x²  - 4x>0

c, 5(3x+1)(4x-3)>0

Answer 1

3(2x+3)(3x-5)<0

\(\Rightarrow\left(3x+3\right)\left(3x-5\right)< 0\)

Mà \(3x+3>3x-5\)

\(\Rightarrow\hept{\begin{cases}3x+3>0\\3x-5< 0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}3x>-3\\3x< 5\end{cases}}\)

\(\Rightarrow-1< x< \frac{5}{3}\)

Answer 2

\(2x^2-4x=2x\left(x-2\right)>0\)

\(\Rightarrow x\left(x-2\right)>0\)

\(\Rightarrow\orbr{\begin{cases}x< 0;x-2< 0\\x>0;x-2>0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x< 0\\x>2\end{cases}}\)