b,x2-2x-35=0
=>(x2-2x+1)-36=0
=>(x-1)2-62=0
=>(x-1-6)(x-1+6)=0
=>(x-7)(x+5)=0
=>x=7 hoặc x=-5
b,x2-2x-35=0
=>(x2-2x+1)-36=0
=>(x-1)2-62=0
=>(x-1-6)(x-1+6)=0
=>(x-7)(x+5)=0
=>x=7 hoặc x=-5
Tìm x:
a) 5x(4-x) + (5x^2-12)=x+6
b) (2x-7) . (5+4x) -8.(x^2-3x+5) = -30
Tìm x:
a)5x(x-2)-2x+4=0
b)2x(x+1)-(x-2)^2=6
c)2x^2+7x-9=0
tìm x:
a)\(\dfrac{-3}{x+5}< 0\) b)\(\dfrac{2x+1}{7}< 0\) c)x\(^2\) - 5x + 4 >0 d)\(\dfrac{x+1}{x-1}< 1\)
tìm x,biết:
a 2x(x-7)+5x-35
b x^3-2x^2+x-3=0
c 4x^2+12x+9=0
d x(x-3)-7x+21=0
Tìm x:
a) x(2-x)+(x2+x)=7
b) (2x+1)2-x(4-5x)=17
c) (4-x)2-(2x+1)2=0
d) (2x3-8x2+10x) : (2x)=0
e) (4x4-16x-48) : (-2x)2=0
1, Tìm x, biết:
A) 2x(x-7)+5x-35=0
B) x(x-3)-7x+21=0
C) x^3-x^2-25x+25=0
Tìm x:
a) 5x+40x4=0
b) 8x2-2x-1=0
c) (3x2+x)2-(3x2+x)-2=0
Giải phương trình:
b) \(5x+2\left(x-7\right)=35\)
d) \(\dfrac{x+2}{x-2}-\dfrac{1}{x}-\dfrac{2}{x^2-2x}=0\)
Tìm x:
a) 5x(x-2)+(2-x)=0
b) x(2x-5)-10x+25=0
c) \(\dfrac{25}{16}\)-4x2+4x-1=0
d)x4+2x2-8=0