a) \(2x\left(x-3\right)-\left(3-x\right)=0\)
\(=2x\left(x-3\right)+\left(x-3\right)=0\)
\(=\left(x-3\right)\left(2x+1\right)=0\)
\(=>\orbr{\begin{cases}x-3=0\\2x+1=0\end{cases}=>\orbr{\begin{cases}x=3\\x=\frac{-1}{2}\end{cases}}}\)
b) \(3x\left(x+5\right)-6\left(x+5\right)=0\)
\(=>\left(x+5\right)\left(3x-6\right)=0\)
\(=>\orbr{\begin{cases}x+5=0\\3x-6=0\end{cases}=>\orbr{\begin{cases}x=-5\\x=\frac{6}{3}=2\end{cases}}}\)
c) \(x^4-x^2=0\)
\(=>\left(x^2-x\right)\left(x^2+x\right)\)
\(=>\orbr{\begin{cases}x^2-x=0\\x^2+x=0\end{cases}=>\orbr{\begin{cases}x=1\\x=-1\end{cases}}}\)
Ủng hộ nha
a. 2x(x-3)-(3-x)=0
=>2x2-6x-3+x=0
=>2x2-5x-3=0
=>2x2+x-6x+3=0
=>x(2x+1)-3(2x+1)=0
=>(x-3)(2x+1)=0
\(\Rightarrow\orbr{\begin{cases}x=3\\x=-\frac{1}{2}\end{cases}}\)
b. 3x(x+5)-6(x+5)=0
=>(3x-6)(x+5)=0
\(\Rightarrow\orbr{\begin{cases}x=-5\\x=2\end{cases}}\)
c. x4 - x2 =0
=>x2(x-1)(x+1)=0
\(\Rightarrow\orbr{\begin{cases}x=0\\x=\pm1\end{cases}}\)
