\(7x\cdot\left(x-10\right)=0\Rightarrow7x=0\)hoặc \(x-10=0\)
\(TH1:7x=0\Rightarrow x=0\)
\(TH2:\left(x-10\right)=0\Rightarrow x=10\)
Vậy \(x=0\)hoặc \(x=10\)
7x.(x-10)=0
->7x^2 -70=0
->7x^2 =70 ->x^2=10 -> x=cân 10
\(7x.\left(x-10\right)=0\)
\(\Rightarrow\orbr{\begin{cases}7x=0\\x-10=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=10\end{cases}}}\)
Vậy x = 0,10