\(\frac{5x+4}{2006}+\frac{5x+3}{2007}=\frac{5x+2}{2008}+\frac{5x+1}{2009}\)
\(\Leftrightarrow\frac{5x+4}{2006}+1+\frac{5x+3}{2007}+1=\frac{5x+2}{2008}+1+\frac{5x+1}{2009}+1\)
\(\Leftrightarrow\frac{5x+2010}{2006}+\frac{5x+2010}{2007}=\frac{5x+2010}{2008}+\frac{5x+2010}{2009}\)
\(\Leftrightarrow\left(5x+2010\right)\left(\frac{1}{2006}+\frac{1}{2007}\right)=\left(5x+2010\right)\left(\frac{1}{2008}+\frac{1}{2009}\right)\)
\(\Leftrightarrow5x+2010=0\)
\(\Leftrightarrow5x=-2010\)
\(\Leftrightarrow x=-402\)
=>\(\frac{5x+4}{2006}+1+\frac{5x+3}{2007}+1=\frac{5x+2}{2008}+1+\frac{5x+1}{2009}+1\)\(+1\)
=>\(\frac{5x+2010}{2006}+\frac{5x+2010}{2007}-\frac{5x+2010}{2008}-\frac{5x+2010}{2009}=0\)
=>(5x+2010)(
=>(5x+2010) (\(\frac{1}{2006}+\frac{1}{2007}-\frac{1}{2008}-\frac{1}{2009}\))=0
vì \(\frac{1}{2006}>\frac{1}{2008};\frac{1}{2007}>\frac{1}{2009}\)nên\(\frac{1}{2006}+\frac{1}{2007}-\frac{1}{2008}-\frac{1}{2009}>0\)
=>5x+2010=0
=>x+402=0
=>x=-402
Vậy x = -402
ok bạn nhé!!!!!!!!!!!!!!!
HOK tốt!!!!!!!!!!!!!!!!!!!!
